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Azo coupling: practice and mechanism

Reagent: C₆H₅N₂⁺ (diazonium salt), 0 °CTopic: Aromatic compoundsAdvanced

The diazonium ion is a weak electrophile and only attacks very electron-rich rings (phenols, dimethylanilines), preferably at para. The N=N group stays: an azo dye forms.

Example

C₆H₅N₂⁺ (diazonium salt), 0 °C

The diazonium ion is a weak electrophile and only attacks very electron-rich rings: phenols (as phenoxide) and dialkylanilines. It couples at the para position, giving an azo compound (Ar–N=N–Ar), usually a dye.

Mechanism step by step

  1. 1

    The aryl diazonium ion (Ar–N≡N⁺) is made beforehand in the cold from aniline, NaNO₂ and HCl.

  2. 2

    The very electron-rich ring (phenoxide or dimethylaniline) attacks the terminal N atom, preferably at para (SEAr).

  3. 3

    Loss of H⁺ restores aromaticity: Ar–N=N–Ar forms, a coloured azo dye.

Practice tasks

Which product forms, which reagent is needed? After each answer you see the explanation.

Task 1 of 1Aromatic compounds
C₆H₅N₂⁺ (diazonium salt), 0 °C
?

Which main product forms?

Typical mistakes

Often confused with: Sandmeyer reaction (chloride) · Nitration (SEAr)

Frequently asked questions

Why are azo compounds coloured?

The N=N group links two aromatic rings into a long conjugated π system that absorbs visible light (yellow to red).

What pH is needed?

Weakly basic for phenols (the phenoxide is richer), weakly acidic for amines. Too basic and the diazonium ion decomposes.

More reactions: Aromatic compounds