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Ketone from acid chloride and cuprate: practice and mechanism

Reagent: (CH₃)₂CuLi, −78 °CTopic: Carboxylic acids & derivativesAdvanced

The cuprate replaces the Cl of the acid chloride by CH₃ and stops at the ketone, because it hardly reacts with ketones.

Example

(CH₃)₂CuLi, −78 °C

Cuprates are less reactive than Grignard reagents: they replace the chloride of the acid chloride by a methyl group but do not attack the ketone formed. The reaction therefore stops at the ketone instead of the tertiary alcohol.

Mechanism step by step

  1. 1

    The cuprate transfers a methyl group to the carbonyl carbon of the acid chloride (often via a copper(III) intermediate).

  2. 2

    Chloride leaves and the ketone forms.

  3. 3

    At −78 °C the cuprate does not react with the ketone; the reaction stops.

Practice tasks

Which product forms, which reagent is needed? After each answer you see the explanation.

Task 1 of 3Carboxylic acids & derivatives
(CH₃)₂CuLi, −78 °C
?

Which main product forms?

Typical mistakes

  • That would be the Grignard product (two additions). Cuprates do not react further with the ketone formed.
  • Hydrolysis to the acid would be the reaction with water. Here the cuprate transfers a methyl group.

Often confused with: Grignard reaction · Ester from acyl chloride

Frequently asked questions

What other routes to ketones are there?

Nitrile + Grignard, Weinreb amide + Grignard, Friedel–Crafts acylation (aryl ketones) and oxidation of secondary alcohols.

Why does Grignard react twice?

The ketone is reactive and still present in the mixture, so a second Grignard adds and gives the tertiary alcohol.

More reactions: Carboxylic acids & derivatives